What are the solutions to the equation (5m+1)^2=7 ?

The solutions to the equation (5m+1)^2=7 are m=(sqrt(7)-1)/5 ,m=(-sqrt(7)-1)/5

Find the zeros of (5m+1)^2=7

The zeros of (5m+1)^2=7 are m=(sqrt(7)-1)/5 ,m=(-sqrt(7)-1)/5

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(5 m + 1)^{2} = 7

m = \frac{7 - 1}{5}, m = \frac{- 7 - 1}{5}

Decimal Notation

m = 0.32915 \dots, m = - 0.72915 \dots

Solution steps

(5 m + 1)^{2} = 7

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

5 m + 1 = 7 : m = \frac{7 - 1}{5}

Solve

5 m + 1 = - 7 : m = \frac{- 7 - 1}{5}

The solutions to the quadratic equation are:

m = \frac{7 - 1}{5}, m = \frac{- 7 - 1}{5}

2 x^{2} + 4 x + 2 = 0

49 x^{2} + 9 = 42 x

z^{2} + 11 z + 16 = 0

(x - \frac{1}{2})^{2} = 0

x^{2} + 3 k + 1 = (k + 2) x

What are the solutions to the equation (5m+1)^2=7 ?
The solutions to the equation (5m+1)^2=7 are m=(sqrt(7)-1)/5 ,m=(-sqrt(7)-1)/5
Find the zeros of (5m+1)^2=7
The zeros of (5m+1)^2=7 are m=(sqrt(7)-1)/5 ,m=(-sqrt(7)-1)/5