What are the solutions to the equation 25v^2-36=0 ?

The solutions to the equation 25v^2-36=0 are v= 6/5 ,v=-6/5

Find the zeros of 25v^2-36=0

The zeros of 25v^2-36=0 are v= 6/5 ,v=-6/5

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25 v^{2} - 36 = 0

v = \frac{6}{5}, v = - \frac{6}{5}

Solution steps

25 v^{2} - 36 = 0

Move

36

to the right side

25 v^{2} = 36

Divide both sides by

25

v^{2} = \frac{36}{25}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

v = \frac{36}{25}, v = - \frac{36}{25}

\frac{36}{25} = \frac{6}{5}

- \frac{36}{25} = - \frac{6}{5}

v = \frac{6}{5}, v = - \frac{6}{5}

2 x^{2} - 24 x + a^{3} = 0

3 x^{2} - 7 x = - 2

(x + 5)^{2} = 48

4 u^{2} - 19 u - 5 = 0

x, 2 x^{2} + 4 x + 2 = 0

What are the solutions to the equation 25v^2-36=0 ?
The solutions to the equation 25v^2-36=0 are v= 6/5 ,v=-6/5
Find the zeros of 25v^2-36=0
The zeros of 25v^2-36=0 are v= 6/5 ,v=-6/5