What are the solutions to the equation 2x^2-24x+a^3=0 ?

The solutions to the equation 2x^2-24x+a^3=0 are x=(24+sqrt(576-8a^3))/4 ,x=(24-sqrt(576-8a^3))/4

Find the zeros of 2x^2-24x+a^3=0

The zeros of 2x^2-24x+a^3=0 are x=(24+sqrt(576-8a^3))/4 ,x=(24-sqrt(576-8a^3))/4

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2 x^{2} - 24 x + a^{3} = 0

x = \frac{24 + 576 - 8 a ^{3}}{4}, x = \frac{24 - 576 - 8 a ^{3}}{4}

Solution steps

2 x^{2} - 24 x + a^{3} = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 24 ) \pm ( - 24 ) ^{2} - 4 \cdot 2 a ^{3}}{2 \cdot 2}

Simplify

(- 24)^{2} - 4 \cdot 2 a^{3} : 576 - 8 a^{3}

x_{1, 2} = \frac{- ( - 24 ) \pm 576 - 8 a ^{3}}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 24 ) + 576 - 8 a ^{3}}{2 \cdot 2}, x_{2} = \frac{- ( - 24 ) - 576 - 8 a ^{3}}{2 \cdot 2}

x = \frac{- ( - 24 ) + 576 - 8 a ^{3}}{2 \cdot 2} : \frac{24 + 576 - 8 a ^{3}}{4}

x = \frac{- ( - 24 ) - 576 - 8 a ^{3}}{2 \cdot 2} : \frac{24 - 576 - 8 a ^{3}}{4}

The solutions to the quadratic equation are:

x = \frac{24 + 576 - 8 a ^{3}}{4}, x = \frac{24 - 576 - 8 a ^{3}}{4}

3 x^{2} - 7 x = - 2

(x + 5)^{2} = 48

4 u^{2} - 19 u - 5 = 0

x, 2 x^{2} + 4 x + 2 = 0

x^{2} - x + 5 = 55

What are the solutions to the equation 2x^2-24x+a^3=0 ?
The solutions to the equation 2x^2-24x+a^3=0 are x=(24+sqrt(576-8a^3))/4 ,x=(24-sqrt(576-8a^3))/4
Find the zeros of 2x^2-24x+a^3=0
The zeros of 2x^2-24x+a^3=0 are x=(24+sqrt(576-8a^3))/4 ,x=(24-sqrt(576-8a^3))/4