What are the solutions to the equation 3x^2-7x=-2 ?

The solutions to the equation 3x^2-7x=-2 are x=2,x= 1/3

Find the zeros of 3x^2-7x=-2

The zeros of 3x^2-7x=-2 are x=2,x= 1/3

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3 x^{2} - 7 x = - 2

x = 2, x = \frac{1}{3}

Solution steps

3 x^{2} - 7 x = - 2

Move

2

to the left side

3 x^{2} - 7 x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 3 \cdot 2}{2 \cdot 3}

(- 7)^{2} - 4 \cdot 3 \cdot 2 = 5

x_{1, 2} = \frac{- ( - 7 ) \pm 5}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 7 ) + 5}{2 \cdot 3}, x_{2} = \frac{- ( - 7 ) - 5}{2 \cdot 3}

x = \frac{- ( - 7 ) + 5}{2 \cdot 3} : 2

x = \frac{- ( - 7 ) - 5}{2 \cdot 3} : \frac{1}{3}

The solutions to the quadratic equation are:

x = 2, x = \frac{1}{3}

(x + 5)^{2} = 48

4 u^{2} - 19 u - 5 = 0

x, 2 x^{2} + 4 x + 2 = 0

x^{2} - x + 5 = 55

2 c^{2} + 3 c + 2 = - 10

What are the solutions to the equation 3x^2-7x=-2 ?
The solutions to the equation 3x^2-7x=-2 are x=2,x= 1/3
Find the zeros of 3x^2-7x=-2
The zeros of 3x^2-7x=-2 are x=2,x= 1/3