What are the solutions to the equation solvefor x,2x^2+4x+2=0 ?

The solutions to the equation solvefor x,2x^2+4x+2=0 are x=-1

Find the zeros of solvefor x,2x^2+4x+2=0

The zeros of solvefor x,2x^2+4x+2=0 are x=-1

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x, 2 x^{2} + 4 x + 2 = 0

x = - 1

Solution steps

2 x^{2} + 4 x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 2 \cdot 2}{2 \cdot 2}

4^{2} - 4 \cdot 2 \cdot 2 = 0

x_{1, 2} = \frac{- 4 \pm 0}{2 \cdot 2}

x = \frac{- 4}{2 \cdot 2}

\frac{- 4}{2 \cdot 2} = - 1

x = - 1

The solution to the quadratic equation is:

x = - 1

x^{2} - x + 5 = 55

2 c^{2} + 3 c + 2 = - 10

2 x^{2} - 16 x = - 24

4 w^{2} - 8 w - 5 = 0

3 x (x - 1) = 6

What are the solutions to the equation solvefor x,2x^2+4x+2=0 ?
The solutions to the equation solvefor x,2x^2+4x+2=0 are x=-1
Find the zeros of solvefor x,2x^2+4x+2=0
The zeros of solvefor x,2x^2+4x+2=0 are x=-1