What are the solutions to the equation (x-1)^2-24=0 ?

The solutions to the equation (x-1)^2-24=0 are x=2sqrt(6)+1,x=-2sqrt(6)+1

Find the zeros of (x-1)^2-24=0

The zeros of (x-1)^2-24=0 are x=2sqrt(6)+1,x=-2sqrt(6)+1

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(x - 1)^{2} - 24 = 0

x = 26 + 1, x = - 26 + 1

Decimal Notation

x = 5.89897 \dots, x = - 3.89897 \dots

Solution steps

(x - 1)^{2} - 24 = 0

Move

24

to the right side

(x - 1)^{2} = 24

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 1 = 24 : x = 26 + 1

Solve

x - 1 = - 24 : x = - 26 + 1

The solutions to the quadratic equation are:

x = 26 + 1, x = - 26 + 1

n^{2} + 5 n - 14 = 0

(x - 2) (3 - 2 x) = 3

(2 y + 9)^{2} = 81

x^{2} - 4 x + 4 = 12

A = 4 π x^{2}

What are the solutions to the equation (x-1)^2-24=0 ?
The solutions to the equation (x-1)^2-24=0 are x=2sqrt(6)+1,x=-2sqrt(6)+1
Find the zeros of (x-1)^2-24=0
The zeros of (x-1)^2-24=0 are x=2sqrt(6)+1,x=-2sqrt(6)+1