What are the solutions to the equation (2y+9)^2=81 ?

The solutions to the equation (2y+9)^2=81 are y=0,y=-9

Find the zeros of (2y+9)^2=81

The zeros of (2y+9)^2=81 are y=0,y=-9

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(2 y + 9)^{2} = 81

y = 0, y = - 9

Solution steps

(2 y + 9)^{2} = 81

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

2 y + 9 = 81 : y = 0

Solve

2 y + 9 = - 81 : y = - 9

The solutions to the quadratic equation are:

y = 0, y = - 9

x^{2} - 4 x + 4 = 12

A = 4 π x^{2}

b^{2} + g = \frac{A}{m}

(8 b - 7)^{2} = 169

x^{2} + 6 x + 10 = 8 x + 25

What are the solutions to the equation (2y+9)^2=81 ?
The solutions to the equation (2y+9)^2=81 are y=0,y=-9
Find the zeros of (2y+9)^2=81
The zeros of (2y+9)^2=81 are y=0,y=-9