What are the solutions to the equation n^2+5n-14=0 ?

The solutions to the equation n^2+5n-14=0 are n=2,n=-7

Find the zeros of n^2+5n-14=0

The zeros of n^2+5n-14=0 are n=2,n=-7

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

n^{2} + 5 n - 14 = 0

n = 2, n = - 7

Solution steps

n^{2} + 5 n - 14 = 0

Solve with the quadratic formula

n_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 1 \cdot ( - 14 )}{2 \cdot 1}

5^{2} - 4 \cdot 1 \cdot (- 14) = 9

n_{1, 2} = \frac{- 5 \pm 9}{2 \cdot 1}

Separate the solutions

n_{1} = \frac{- 5 + 9}{2 \cdot 1}, n_{2} = \frac{- 5 - 9}{2 \cdot 1}

n = \frac{- 5 + 9}{2 \cdot 1} : 2

n = \frac{- 5 - 9}{2 \cdot 1} : - 7

The solutions to the quadratic equation are:

n = 2, n = - 7

(x - 2) (3 - 2 x) = 3

(2 y + 9)^{2} = 81

x^{2} - 4 x + 4 = 12

A = 4 π x^{2}

b^{2} + g = \frac{A}{m}

What are the solutions to the equation n^2+5n-14=0 ?
The solutions to the equation n^2+5n-14=0 are n=2,n=-7
Find the zeros of n^2+5n-14=0
The zeros of n^2+5n-14=0 are n=2,n=-7