What are the solutions to the equation A=4pix^2 ?

The solutions to the equation A=4pix^2 are x=(sqrt(A))/(2sqrt(pi)),x=-(sqrt(A))/(2sqrt(pi))

Find the zeros of A=4pix^2

The zeros of A=4pix^2 are x=(sqrt(A))/(2sqrt(pi)),x=-(sqrt(A))/(2sqrt(pi))

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A = 4 π x^{2}

x = \frac{A}{2 π}, x = - \frac{A}{2 π}

Solution steps

A = 4 π x^{2}

Switch sides

4 π x^{2} = A

Divide both sides by

4 π

x^{2} = \frac{A}{4 π}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{A}{4 π}, x = - \frac{A}{4 π}

Simplify

\frac{A}{4 π} : \frac{A}{2 π}

Simplify

- \frac{A}{4 π} : - \frac{A}{2 π}

x = \frac{A}{2 π}, x = - \frac{A}{2 π}

b^{2} + g = \frac{A}{m}

(8 b - 7)^{2} = 169

x^{2} + 6 x + 10 = 8 x + 25

75 - t^{2} = 0

(x + 4)^{2} - 3 = 0

What are the solutions to the equation A=4pix^2 ?
The solutions to the equation A=4pix^2 are x=(sqrt(A))/(2sqrt(pi)),x=-(sqrt(A))/(2sqrt(pi))
Find the zeros of A=4pix^2
The zeros of A=4pix^2 are x=(sqrt(A))/(2sqrt(pi)),x=-(sqrt(A))/(2sqrt(pi))