What are the solutions to the equation b^2+g= A/m ?

The solutions to the equation b^2+g= A/m are b=sqrt(A/m-g),b=-sqrt(A/m-g)

Find the zeros of b^2+g= A/m

The zeros of b^2+g= A/m are b=sqrt(A/m-g),b=-sqrt(A/m-g)

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b^{2} + g = \frac{A}{m}

b = \frac{A}{m} - g, b = - \frac{A}{m} - g

Solution steps

b^{2} + g = \frac{A}{m}

Move

g

to the right side

b^{2} = \frac{A}{m} - g

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

b = \frac{A}{m} - g, b = - \frac{A}{m} - g

(8 b - 7)^{2} = 169

x^{2} + 6 x + 10 = 8 x + 25

75 - t^{2} = 0

(x + 4)^{2} - 3 = 0

a^{0} = x^{2} + 6 x + 9

What are the solutions to the equation b^2+g= A/m ?
The solutions to the equation b^2+g= A/m are b=sqrt(A/m-g),b=-sqrt(A/m-g)
Find the zeros of b^2+g= A/m
The zeros of b^2+g= A/m are b=sqrt(A/m-g),b=-sqrt(A/m-g)