What are the solutions to the equation x^2+6x+10=8x+25 ?

The solutions to the equation x^2+6x+10=8x+25 are x=5,x=-3

Find the zeros of x^2+6x+10=8x+25

The zeros of x^2+6x+10=8x+25 are x=5,x=-3

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x^{2} + 6 x + 10 = 8 x + 25

x = 5, x = - 3

Solution steps

x^{2} + 6 x + 10 = 8 x + 25

Move

25

to the left side

x^{2} + 6 x - 15 = 8 x

Move

8 x

to the left side

x^{2} - 2 x - 15 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot ( - 15 )}{2 \cdot 1}

(- 2)^{2} - 4 \cdot 1 \cdot (- 15) = 8

x_{1, 2} = \frac{- ( - 2 ) \pm 8}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 8}{2 \cdot 1}, x_{2} = \frac{- ( - 2 ) - 8}{2 \cdot 1}

x = \frac{- ( - 2 ) + 8}{2 \cdot 1} : 5

x = \frac{- ( - 2 ) - 8}{2 \cdot 1} : - 3

The solutions to the quadratic equation are:

x = 5, x = - 3

75 - t^{2} = 0

(x + 4)^{2} - 3 = 0

a^{0} = x^{2} + 6 x + 9

- 6 x^{2} + 64 x - 222 = - 8 x

12 x^{2} - 20 x + 3 = 0

What are the solutions to the equation x^2+6x+10=8x+25 ?
The solutions to the equation x^2+6x+10=8x+25 are x=5,x=-3
Find the zeros of x^2+6x+10=8x+25
The zeros of x^2+6x+10=8x+25 are x=5,x=-3