What are the solutions to the equation (x+4)^2-3=0 ?

The solutions to the equation (x+4)^2-3=0 are x=sqrt(3)-4,x=-sqrt(3)-4

Find the zeros of (x+4)^2-3=0

The zeros of (x+4)^2-3=0 are x=sqrt(3)-4,x=-sqrt(3)-4

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(x + 4)^{2} - 3 = 0

x = 3 - 4, x = - 3 - 4

Solution steps

(x + 4)^{2} - 3 = 0

Move

3

to the right side

(x + 4)^{2} = 3

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 4 = 3 : x = 3 - 4

Solve

x + 4 = - 3 : x = - 3 - 4

The solutions to the quadratic equation are:

x = 3 - 4, x = - 3 - 4

a^{0} = x^{2} + 6 x + 9

- 6 x^{2} + 64 x - 222 = - 8 x

12 x^{2} - 20 x + 3 = 0

- 2 x^{2} + 3 x + 3 = 0

5 (x + 3)^{2} = 2

What are the solutions to the equation (x+4)^2-3=0 ?
The solutions to the equation (x+4)^2-3=0 are x=sqrt(3)-4,x=-sqrt(3)-4
Find the zeros of (x+4)^2-3=0
The zeros of (x+4)^2-3=0 are x=sqrt(3)-4,x=-sqrt(3)-4