What are the solutions to the equation a^0=x^2+6x+9 ?

The solutions to the equation a^0=x^2+6x+9 are x=-2,x=-4

Find the zeros of a^0=x^2+6x+9

The zeros of a^0=x^2+6x+9 are x=-2,x=-4

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a^{0} = x^{2} + 6 x + 9

x = - 2, x = - 4

Solution steps

a^{0} = x^{2} + 6 x + 9

Refine

1 = x^{2} + 6 x + 9

Switch sides

x^{2} + 6 x + 9 = 1

Move

1

to the left side

x^{2} + 6 x + 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 1 \cdot 8}{2 \cdot 1}

6^{2} - 4 \cdot 1 \cdot 8 = 2

x_{1, 2} = \frac{- 6 \pm 2}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 6 + 2}{2 \cdot 1}, x_{2} = \frac{- 6 - 2}{2 \cdot 1}

x = \frac{- 6 + 2}{2 \cdot 1} : - 2

x = \frac{- 6 - 2}{2 \cdot 1} : - 4

The solutions to the quadratic equation are:

x = - 2, x = - 4

- 6 x^{2} + 64 x - 222 = - 8 x

12 x^{2} - 20 x + 3 = 0

- 2 x^{2} + 3 x + 3 = 0

5 (x + 3)^{2} = 2

x, y = 3 - x^{2}

What are the solutions to the equation a^0=x^2+6x+9 ?
The solutions to the equation a^0=x^2+6x+9 are x=-2,x=-4
Find the zeros of a^0=x^2+6x+9
The zeros of a^0=x^2+6x+9 are x=-2,x=-4