What are the solutions to the equation 11x^2-4x+11=0 ?

The solutions to the equation 11x^2-4x+11=0 are x= 2/11+i(3sqrt(13))/(11),x= 2/11-i(3sqrt(13))/(11)

Find the zeros of 11x^2-4x+11=0

The zeros of 11x^2-4x+11=0 are x= 2/11+i(3sqrt(13))/(11),x= 2/11-i(3sqrt(13))/(11)

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11 x^{2} - 4 x + 11 = 0

x = \frac{2}{11} + i \frac{3 13}{11}, x = \frac{2}{11} - i \frac{3 13}{11}

Solution steps

11 x^{2} - 4 x + 11 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 11 \cdot 11}{2 \cdot 11}

Simplify

(- 4)^{2} - 4 \cdot 11 \cdot 11 : 613 i

x_{1, 2} = \frac{- ( - 4 ) \pm 6 13 i}{2 \cdot 11}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 6 13 i}{2 \cdot 11}, x_{2} = \frac{- ( - 4 ) - 6 13 i}{2 \cdot 11}

x = \frac{- ( - 4 ) + 6 13 i}{2 \cdot 11} : \frac{2}{11} + i \frac{3 13}{11}

x = \frac{- ( - 4 ) - 6 13 i}{2 \cdot 11} : \frac{2}{11} - i \frac{3 13}{11}

The solutions to the quadratic equation are:

x = \frac{2}{11} + i \frac{3 13}{11}, x = \frac{2}{11} - i \frac{3 13}{11}

X^{2} - 7 X - 18 = 0

x (1 - x) + (- 0.02) - 0.1 x = 0

3 x^{2} + (0 + 1) x - 2 = 0

2 z^{2} - 11 = - 4

5 k^{2} - 17 k + 13 = 0

What are the solutions to the equation 11x^2-4x+11=0 ?
The solutions to the equation 11x^2-4x+11=0 are x= 2/11+i(3sqrt(13))/(11),x= 2/11-i(3sqrt(13))/(11)
Find the zeros of 11x^2-4x+11=0
The zeros of 11x^2-4x+11=0 are x= 2/11+i(3sqrt(13))/(11),x= 2/11-i(3sqrt(13))/(11)