What are the solutions to the equation x(1-x)+(-0.02)-0.1x=0 ?

The solutions to the equation x(1-x)+(-0.02)-0.1x=0 are x=(9-sqrt(73))/(20),x=(9+sqrt(73))/(20)

Find the zeros of x(1-x)+(-0.02)-0.1x=0

The zeros of x(1-x)+(-0.02)-0.1x=0 are x=(9-sqrt(73))/(20),x=(9+sqrt(73))/(20)

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x (1 - x) + (- 0.02) - 0.1 x = 0

x = \frac{9 - 73}{20}, x = \frac{9 + 73}{20}

Decimal Notation

x = 0.02279 \dots, x = 0.87720 \dots

Solution steps

x (1 - x) + (- 0.02) - 0.1 x = 0

Multiply both sides by

100

100 x (1 - x) - 2 - 10 x = 0

Expand

100 x (1 - x) - 2 - 10 x : - 100 x^{2} + 90 x - 2

- 100 x^{2} + 90 x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 90 \pm 9 0 ^{2} - 4 ( - 100 ) ( - 2 )}{2 ( - 100 )}

9 0^{2} - 4 (- 100) (- 2) = 1073

x_{1, 2} = \frac{- 90 \pm 10 73}{2 ( - 100 )}

Separate the solutions

x_{1} = \frac{- 90 + 10 73}{2 ( - 100 )}, x_{2} = \frac{- 90 - 10 73}{2 ( - 100 )}

x = \frac{- 90 + 10 73}{2 ( - 100 )} : \frac{9 - 73}{20}

x = \frac{- 90 - 10 73}{2 ( - 100 )} : \frac{9 + 73}{20}

The solutions to the quadratic equation are:

x = \frac{9 - 73}{20}, x = \frac{9 + 73}{20}

3 x^{2} + (0 + 1) x - 2 = 0

2 z^{2} - 11 = - 4

5 k^{2} - 17 k + 13 = 0

2 x^{2} + 3 = 5

4 (x - 3)^{2} - 27 = - 11

What are the solutions to the equation x(1-x)+(-0.02)-0.1x=0 ?
The solutions to the equation x(1-x)+(-0.02)-0.1x=0 are x=(9-sqrt(73))/(20),x=(9+sqrt(73))/(20)
Find the zeros of x(1-x)+(-0.02)-0.1x=0
The zeros of x(1-x)+(-0.02)-0.1x=0 are x=(9-sqrt(73))/(20),x=(9+sqrt(73))/(20)