What are the solutions to the equation 2z^2-11=-4 ?

The solutions to the equation 2z^2-11=-4 are z=sqrt(7/2),z=-sqrt(7/2)

Find the zeros of 2z^2-11=-4

The zeros of 2z^2-11=-4 are z=sqrt(7/2),z=-sqrt(7/2)

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2 z^{2} - 11 = - 4

z = \frac{7}{2}, z = - \frac{7}{2}

Decimal Notation

z = 1.87082 \dots, z = - 1.87082 \dots

Solution steps

2 z^{2} - 11 = - 4

Move

11

to the right side

2 z^{2} = 7

Divide both sides by

2

z^{2} = \frac{7}{2}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

z = \frac{7}{2}, z = - \frac{7}{2}

5 k^{2} - 17 k + 13 = 0

2 x^{2} + 3 = 5

4 (x - 3)^{2} - 27 = - 11

14 x^{2} - 4 x = 35 x - 10

n (n + 6) = 520

What are the solutions to the equation 2z^2-11=-4 ?
The solutions to the equation 2z^2-11=-4 are z=sqrt(7/2),z=-sqrt(7/2)
Find the zeros of 2z^2-11=-4
The zeros of 2z^2-11=-4 are z=sqrt(7/2),z=-sqrt(7/2)