What are the solutions to the equation 3x^2+(0+1)x-2=0 ?

The solutions to the equation 3x^2+(0+1)x-2=0 are x= 2/3 ,x=-1

Find the zeros of 3x^2+(0+1)x-2=0

The zeros of 3x^2+(0+1)x-2=0 are x= 2/3 ,x=-1

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3 x^{2} + (0 + 1) x - 2 = 0

x = \frac{2}{3}, x = - 1

Solution steps

3 x^{2} + (0 + 1) x - 2 = 0

Expand

3 x^{2} + (0 + 1) x - 2 : 3 x^{2} + x - 2

3 x^{2} + x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 3 ( - 2 )}{2 \cdot 3}

1^{2} - 4 \cdot 3 (- 2) = 5

x_{1, 2} = \frac{- 1 \pm 5}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 1 + 5}{2 \cdot 3}, x_{2} = \frac{- 1 - 5}{2 \cdot 3}

x = \frac{- 1 + 5}{2 \cdot 3} : \frac{2}{3}

x = \frac{- 1 - 5}{2 \cdot 3} : - 1

The solutions to the quadratic equation are:

x = \frac{2}{3}, x = - 1

2 z^{2} - 11 = - 4

5 k^{2} - 17 k + 13 = 0

2 x^{2} + 3 = 5

4 (x - 3)^{2} - 27 = - 11

14 x^{2} - 4 x = 35 x - 10

What are the solutions to the equation 3x^2+(0+1)x-2=0 ?
The solutions to the equation 3x^2+(0+1)x-2=0 are x= 2/3 ,x=-1
Find the zeros of 3x^2+(0+1)x-2=0
The zeros of 3x^2+(0+1)x-2=0 are x= 2/3 ,x=-1