What are the solutions to the equation 6x^2-4x=2 ?

The solutions to the equation 6x^2-4x=2 are x=1,x=-1/3

Find the zeros of 6x^2-4x=2

The zeros of 6x^2-4x=2 are x=1,x=-1/3

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6 x^{2} - 4 x = 2

x = 1, x = - \frac{1}{3}

Decimal Notation

x = 1, x = - 0.33333 \dots

Solution steps

6 x^{2} - 4 x = 2

Move

2

to the left side

6 x^{2} - 4 x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 6 ( - 2 )}{2 \cdot 6}

(- 4)^{2} - 4 \cdot 6 (- 2) = 8

x_{1, 2} = \frac{- ( - 4 ) \pm 8}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 8}{2 \cdot 6}, x_{2} = \frac{- ( - 4 ) - 8}{2 \cdot 6}

x = \frac{- ( - 4 ) + 8}{2 \cdot 6} : 1

x = \frac{- ( - 4 ) - 8}{2 \cdot 6} : - \frac{1}{3}

The solutions to the quadratic equation are:

x = 1, x = - \frac{1}{3}

6 m^{2} + 26 m = 20

3 b^{2} = 1

(2 x + 4)^{2} = 21

5 = - 0.04 t^{2} + 0.8 t + 10

x, z^{2} = 9 x^{2} + y^{2}

What are the solutions to the equation 6x^2-4x=2 ?
The solutions to the equation 6x^2-4x=2 are x=1,x=-1/3
Find the zeros of 6x^2-4x=2
The zeros of 6x^2-4x=2 are x=1,x=-1/3