What are the solutions to the equation (x-2)^2-5=0 ?

The solutions to the equation (x-2)^2-5=0 are x=sqrt(5)+2,x=-sqrt(5)+2

Find the zeros of (x-2)^2-5=0

The zeros of (x-2)^2-5=0 are x=sqrt(5)+2,x=-sqrt(5)+2

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(x - 2)^{2} - 5 = 0

x = 5 + 2, x = - 5 + 2

Decimal Notation

x = 4.23606 \dots, x = - 0.23606 \dots

Solution steps

(x - 2)^{2} - 5 = 0

Move

5

to the right side

(x - 2)^{2} = 5

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 2 = 5 : x = 5 + 2

Solve

x - 2 = - 5 : x = - 5 + 2

The solutions to the quadratic equation are:

x = 5 + 2, x = - 5 + 2

(2 w + 1) w = 66

a, x = a^{2} + b^{2} + c^{3}

x^{2} - 3 x = 7 x^{2} + 5 x

2 x (x - 5) = - 3 x - 3

(x - 6) (x + 2) + x^{2} + 4 = (x - 4) (x - 1)

What are the solutions to the equation (x-2)^2-5=0 ?
The solutions to the equation (x-2)^2-5=0 are x=sqrt(5)+2,x=-sqrt(5)+2
Find the zeros of (x-2)^2-5=0
The zeros of (x-2)^2-5=0 are x=sqrt(5)+2,x=-sqrt(5)+2