What are the solutions to the equation (7z+1)^2=-1 ?

The solutions to the equation (7z+1)^2=-1 are z=-1/7+i 1/7 ,z=-1/7-i 1/7

Find the zeros of (7z+1)^2=-1

The zeros of (7z+1)^2=-1 are z=-1/7+i 1/7 ,z=-1/7-i 1/7

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(7 z + 1)^{2} = - 1

z = - \frac{1}{7} + i \frac{1}{7}, z = - \frac{1}{7} - i \frac{1}{7}

Solution steps

(7 z + 1)^{2} = - 1

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

7 z + 1 = - 1 : z = - \frac{1}{7} + i \frac{1}{7}

Solve

7 z + 1 = - - 1 : z = - \frac{1}{7} - i \frac{1}{7}

The solutions to the quadratic equation are:

z = - \frac{1}{7} + i \frac{1}{7}, z = - \frac{1}{7} - i \frac{1}{7}

z^{2} - 3 z - 7 = 0

(x - 4)^{2} - 9 = x

- 25 x^{2} + 144 = 0

t^{2} - 6 t - 1 = 0

- 16 x^{2} + 40 x + 62 = 0

What are the solutions to the equation (7z+1)^2=-1 ?
The solutions to the equation (7z+1)^2=-1 are z=-1/7+i 1/7 ,z=-1/7-i 1/7
Find the zeros of (7z+1)^2=-1
The zeros of (7z+1)^2=-1 are z=-1/7+i 1/7 ,z=-1/7-i 1/7