What are the solutions to the equation x^2-x-2=28 ?

The solutions to the equation x^2-x-2=28 are x=6,x=-5

Find the zeros of x^2-x-2=28

The zeros of x^2-x-2=28 are x=6,x=-5

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x^{2} - x - 2 = 28

x = 6, x = - 5

Solution steps

x^{2} - x - 2 = 28

Move

28

to the left side

x^{2} - x - 30 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 1 \cdot ( - 30 )}{2 \cdot 1}

(- 1)^{2} - 4 \cdot 1 \cdot (- 30) = 11

x_{1, 2} = \frac{- ( - 1 ) \pm 11}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 11}{2 \cdot 1}, x_{2} = \frac{- ( - 1 ) - 11}{2 \cdot 1}

x = \frac{- ( - 1 ) + 11}{2 \cdot 1} : 6

x = \frac{- ( - 1 ) - 11}{2 \cdot 1} : - 5

The solutions to the quadratic equation are:

x = 6, x = - 5

y^{2} - 14 y + 49 = 9

\frac{m ^{2}}{4} - 2 m + 4 = 0

64 (x - 1)^{2} = 289

\frac{9 x ^{2} - 25}{4} = 0

z^{2} + z - 3 = 0

What are the solutions to the equation x^2-x-2=28 ?
The solutions to the equation x^2-x-2=28 are x=6,x=-5
Find the zeros of x^2-x-2=28
The zeros of x^2-x-2=28 are x=6,x=-5