What are the solutions to the equation u^2-6u-7=0 ?

The solutions to the equation u^2-6u-7=0 are u=7,u=-1

Find the zeros of u^2-6u-7=0

The zeros of u^2-6u-7=0 are u=7,u=-1

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u^{2} - 6 u - 7 = 0

u = 7, u = - 1

Solution steps

u^{2} - 6 u - 7 = 0

Solve with the quadratic formula

u_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 1 \cdot ( - 7 )}{2 \cdot 1}

(- 6)^{2} - 4 \cdot 1 \cdot (- 7) = 8

u_{1, 2} = \frac{- ( - 6 ) \pm 8}{2 \cdot 1}

Separate the solutions

u_{1} = \frac{- ( - 6 ) + 8}{2 \cdot 1}, u_{2} = \frac{- ( - 6 ) - 8}{2 \cdot 1}

u = \frac{- ( - 6 ) + 8}{2 \cdot 1} : 7

u = \frac{- ( - 6 ) - 8}{2 \cdot 1} : - 1

The solutions to the quadratic equation are:

u = 7, u = - 1

x^{2} - x - 2 = 28

y^{2} - 14 y + 49 = 9

\frac{m ^{2}}{4} - 2 m + 4 = 0

64 (x - 1)^{2} = 289

\frac{9 x ^{2} - 25}{4} = 0

What are the solutions to the equation u^2-6u-7=0 ?
The solutions to the equation u^2-6u-7=0 are u=7,u=-1
Find the zeros of u^2-6u-7=0
The zeros of u^2-6u-7=0 are u=7,u=-1