What are the solutions to the equation y^2-14y+49=9 ?

The solutions to the equation y^2-14y+49=9 are y=10,y=4

Find the zeros of y^2-14y+49=9

The zeros of y^2-14y+49=9 are y=10,y=4

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y^{2} - 14 y + 49 = 9

y = 10, y = 4

Solution steps

y^{2} - 14 y + 49 = 9

Move

9

to the left side

y^{2} - 14 y + 40 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 14 ) \pm ( - 14 ) ^{2} - 4 \cdot 1 \cdot 40}{2 \cdot 1}

(- 14)^{2} - 4 \cdot 1 \cdot 40 = 6

y_{1, 2} = \frac{- ( - 14 ) \pm 6}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- ( - 14 ) + 6}{2 \cdot 1}, y_{2} = \frac{- ( - 14 ) - 6}{2 \cdot 1}

y = \frac{- ( - 14 ) + 6}{2 \cdot 1} : 10

y = \frac{- ( - 14 ) - 6}{2 \cdot 1} : 4

The solutions to the quadratic equation are:

y = 10, y = 4

\frac{m ^{2}}{4} - 2 m + 4 = 0

64 (x - 1)^{2} = 289

\frac{9 x ^{2} - 25}{4} = 0

z^{2} + z - 3 = 0

2 (y^{2} + 3) = 11 - 13 y

What are the solutions to the equation y^2-14y+49=9 ?
The solutions to the equation y^2-14y+49=9 are y=10,y=4
Find the zeros of y^2-14y+49=9
The zeros of y^2-14y+49=9 are y=10,y=4