What are the solutions to the equation -(x-6)^2+6=-11 ?

The solutions to the equation -(x-6)^2+6=-11 are x=sqrt(17)+6,x=-sqrt(17)+6

Find the zeros of -(x-6)^2+6=-11

The zeros of -(x-6)^2+6=-11 are x=sqrt(17)+6,x=-sqrt(17)+6

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- (x - 6)^{2} + 6 = - 11

x = 17 + 6, x = - 17 + 6

Decimal Notation

x = 10.12310 \dots, x = 1.87689 \dots

Solution steps

- (x - 6)^{2} + 6 = - 11

Move

6

to the right side

- (x - 6)^{2} = - 17

Divide both sides by

- 1

(x - 6)^{2} = 17

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 6 = 17 : x = 17 + 6

Solve

x - 6 = - 17 : x = - 17 + 6

The solutions to the quadratic equation are:

x = 17 + 6, x = - 17 + 6

9 x^{2} - 6 x + 1 = 0

- 4 x^{2} + 7 x - 1 = 0

4 - 4 x \cdot (- 4 x + 1) = 0

9 x^{2} + 6 x + 1 = 16

4 (x + 2)^{2} - 4 = 0

What are the solutions to the equation -(x-6)^2+6=-11 ?
The solutions to the equation -(x-6)^2+6=-11 are x=sqrt(17)+6,x=-sqrt(17)+6
Find the zeros of -(x-6)^2+6=-11
The zeros of -(x-6)^2+6=-11 are x=sqrt(17)+6,x=-sqrt(17)+6