What are the solutions to the equation x^2+2=4x ?

The solutions to the equation x^2+2=4x are x=2+sqrt(2),x=2-sqrt(2)

Find the zeros of x^2+2=4x

The zeros of x^2+2=4x are x=2+sqrt(2),x=2-sqrt(2)

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x^{2} + 2 = 4 x

x = 2 + 2, x = 2 - 2

Solution steps

x^{2} + 2 = 4 x

Move

4 x

to the left side

x^{2} + 2 - 4 x = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} - 4 x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot 2}{2 \cdot 1}

(- 4)^{2} - 4 \cdot 1 \cdot 2 = 22

x_{1, 2} = \frac{- ( - 4 ) \pm 2 2}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 2 2}{2 \cdot 1}, x_{2} = \frac{- ( - 4 ) - 2 2}{2 \cdot 1}

x = \frac{- ( - 4 ) + 2 2}{2 \cdot 1} : 2 + 2

x = \frac{- ( - 4 ) - 2 2}{2 \cdot 1} : 2 - 2

The solutions to the quadratic equation are:

x = 2 + 2, x = 2 - 2

- (x - 6)^{2} + 6 = - 11

9 x^{2} - 6 x + 1 = 0

- 4 x^{2} + 7 x - 1 = 0

4 - 4 x \cdot (- 4 x + 1) = 0

9 x^{2} + 6 x + 1 = 16

What are the solutions to the equation x^2+2=4x ?
The solutions to the equation x^2+2=4x are x=2+sqrt(2),x=2-sqrt(2)
Find the zeros of x^2+2=4x
The zeros of x^2+2=4x are x=2+sqrt(2),x=2-sqrt(2)