What are the solutions to the equation -4x^2+7x-1=0 ?

The solutions to the equation -4x^2+7x-1=0 are x=(7-sqrt(33))/8 ,x=(7+sqrt(33))/8

Find the zeros of -4x^2+7x-1=0

The zeros of -4x^2+7x-1=0 are x=(7-sqrt(33))/8 ,x=(7+sqrt(33))/8

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- 4 x^{2} + 7 x - 1 = 0

x = \frac{7 - 33}{8}, x = \frac{7 + 33}{8}

Solution steps

- 4 x^{2} + 7 x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 ( - 4 ) ( - 1 )}{2 ( - 4 )}

7^{2} - 4 (- 4) (- 1) = 33

x_{1, 2} = \frac{- 7 \pm 33}{2 ( - 4 )}

Separate the solutions

x_{1} = \frac{- 7 + 33}{2 ( - 4 )}, x_{2} = \frac{- 7 - 33}{2 ( - 4 )}

x = \frac{- 7 + 33}{2 ( - 4 )} : \frac{7 - 33}{8}

x = \frac{- 7 - 33}{2 ( - 4 )} : \frac{7 + 33}{8}

The solutions to the quadratic equation are:

x = \frac{7 - 33}{8}, x = \frac{7 + 33}{8}

4 - 4 x \cdot (- 4 x + 1) = 0

9 x^{2} + 6 x + 1 = 16

4 (x + 2)^{2} - 4 = 0

x, 3 y^{2} + 5 x y = 2 x^{2}

3 q^{2} - 108 q + 890 = 0

What are the solutions to the equation -4x^2+7x-1=0 ?
The solutions to the equation -4x^2+7x-1=0 are x=(7-sqrt(33))/8 ,x=(7+sqrt(33))/8
Find the zeros of -4x^2+7x-1=0
The zeros of -4x^2+7x-1=0 are x=(7-sqrt(33))/8 ,x=(7+sqrt(33))/8