What are the solutions to the equation 9x^2+6x+1=16 ?

The solutions to the equation 9x^2+6x+1=16 are x=1,x=-5/3

Find the zeros of 9x^2+6x+1=16

The zeros of 9x^2+6x+1=16 are x=1,x=-5/3

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9 x^{2} + 6 x + 1 = 16

x = 1, x = - \frac{5}{3}

Solution steps

9 x^{2} + 6 x + 1 = 16

Move

16

to the left side

9 x^{2} + 6 x - 15 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 9 ( - 15 )}{2 \cdot 9}

6^{2} - 4 \cdot 9 (- 15) = 24

x_{1, 2} = \frac{- 6 \pm 24}{2 \cdot 9}

Separate the solutions

x_{1} = \frac{- 6 + 24}{2 \cdot 9}, x_{2} = \frac{- 6 - 24}{2 \cdot 9}

x = \frac{- 6 + 24}{2 \cdot 9} : 1

x = \frac{- 6 - 24}{2 \cdot 9} : - \frac{5}{3}

The solutions to the quadratic equation are:

x = 1, x = - \frac{5}{3}

4 (x + 2)^{2} - 4 = 0

x, 3 y^{2} + 5 x y = 2 x^{2}

3 q^{2} - 108 q + 890 = 0

x (2 x - 7) = 15

x^{2} - 9 x = 7

What are the solutions to the equation 9x^2+6x+1=16 ?
The solutions to the equation 9x^2+6x+1=16 are x=1,x=-5/3
Find the zeros of 9x^2+6x+1=16
The zeros of 9x^2+6x+1=16 are x=1,x=-5/3