What are the solutions to the equation 4-4x*(-4x+1)=0 ?

The solutions to the equation 4-4x*(-4x+1)=0 are x= 1/8+i(sqrt(15))/8 ,x= 1/8-i(sqrt(15))/8

Find the zeros of 4-4x*(-4x+1)=0

The zeros of 4-4x*(-4x+1)=0 are x= 1/8+i(sqrt(15))/8 ,x= 1/8-i(sqrt(15))/8

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4 - 4 x \cdot (- 4 x + 1) = 0

x = \frac{1}{8} + i \frac{15}{8}, x = \frac{1}{8} - i \frac{15}{8}

Solution steps

4 - 4 x (- 4 x + 1) = 0

Expand

4 - 4 x (- 4 x + 1) : 4 + 16 x^{2} - 4 x

4 + 16 x^{2} - 4 x = 0

Write in the standard form

a x^{2} + b x + c = 0

16 x^{2} - 4 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 16 \cdot 4}{2 \cdot 16}

Simplify

(- 4)^{2} - 4 \cdot 16 \cdot 4 : 415 i

x_{1, 2} = \frac{- ( - 4 ) \pm 4 15 i}{2 \cdot 16}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 4 15 i}{2 \cdot 16}, x_{2} = \frac{- ( - 4 ) - 4 15 i}{2 \cdot 16}

x = \frac{- ( - 4 ) + 4 15 i}{2 \cdot 16} : \frac{1}{8} + i \frac{15}{8}

x = \frac{- ( - 4 ) - 4 15 i}{2 \cdot 16} : \frac{1}{8} - i \frac{15}{8}

The solutions to the quadratic equation are:

x = \frac{1}{8} + i \frac{15}{8}, x = \frac{1}{8} - i \frac{15}{8}

9 x^{2} + 6 x + 1 = 16

4 (x + 2)^{2} - 4 = 0

x, 3 y^{2} + 5 x y = 2 x^{2}

3 q^{2} - 108 q + 890 = 0

x (2 x - 7) = 15

What are the solutions to the equation 4-4x*(-4x+1)=0 ?
The solutions to the equation 4-4x*(-4x+1)=0 are x= 1/8+i(sqrt(15))/8 ,x= 1/8-i(sqrt(15))/8
Find the zeros of 4-4x*(-4x+1)=0
The zeros of 4-4x*(-4x+1)=0 are x= 1/8+i(sqrt(15))/8 ,x= 1/8-i(sqrt(15))/8