What are the solutions to the equation solvefor x,3y^2+5xy=2x^2 ?

The solutions to the equation solvefor x,3y^2+5xy=2x^2 are x=3y,x=-y/2

Find the zeros of solvefor x,3y^2+5xy=2x^2

The zeros of solvefor x,3y^2+5xy=2x^2 are x=3y,x=-y/2

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solve for

x, 3 y^{2} + 5 x y = 2 x^{2}

x = 3 y, x = - \frac{y}{2}

Solution steps

3 y^{2} + 5 x y = 2 x^{2}

Switch sides

2 x^{2} = 3 y^{2} + 5 x y

Move

5 x y

to the left side

2 x^{2} - 5 x y = 3 y^{2}

Move

3 y^{2}

to the left side

2 x^{2} - 5 x y - 3 y^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

2 x^{2} - 5 y x - 3 y^{2} = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 y ) \pm ( - 5 y ) ^{2} - 4 \cdot 2 ( - 3 y ^{2} )}{2 \cdot 2}

Simplify

(- 5 y)^{2} - 4 \cdot 2 (- 3 y^{2}) : 7 y

x_{1, 2} = \frac{- ( - 5 y ) \pm 7 y}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 5 y ) + 7 y}{2 \cdot 2}, x_{2} = \frac{- ( - 5 y ) - 7 y}{2 \cdot 2}

x = \frac{- ( - 5 y ) + 7 y}{2 \cdot 2} : 3 y

x = \frac{- ( - 5 y ) - 7 y}{2 \cdot 2} : - \frac{y}{2}

The solutions to the quadratic equation are:

x = 3 y, x = - \frac{y}{2}

3 q^{2} - 108 q + 890 = 0

x (2 x - 7) = 15

x^{2} - 9 x = 7

7 x^{2} - 78 x = 0

x^{2} - 3 = 9

What are the solutions to the equation solvefor x,3y^2+5xy=2x^2 ?
The solutions to the equation solvefor x,3y^2+5xy=2x^2 are x=3y,x=-y/2
Find the zeros of solvefor x,3y^2+5xy=2x^2
The zeros of solvefor x,3y^2+5xy=2x^2 are x=3y,x=-y/2