What are the solutions to the equation 4k^2+41k+10=0 ?

The solutions to the equation 4k^2+41k+10=0 are k=-1/4 ,k=-10

Find the zeros of 4k^2+41k+10=0

The zeros of 4k^2+41k+10=0 are k=-1/4 ,k=-10

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4 k^{2} + 41 k + 10 = 0

k = - \frac{1}{4}, k = - 10

Solution steps

4 k^{2} + 41 k + 10 = 0

Solve with the quadratic formula

k_{1, 2} = \frac{- 41 \pm 4 1 ^{2} - 4 \cdot 4 \cdot 10}{2 \cdot 4}

4 1^{2} - 4 \cdot 4 \cdot 10 = 39

k_{1, 2} = \frac{- 41 \pm 39}{2 \cdot 4}

Separate the solutions

k_{1} = \frac{- 41 + 39}{2 \cdot 4}, k_{2} = \frac{- 41 - 39}{2 \cdot 4}

k = \frac{- 41 + 39}{2 \cdot 4} : - \frac{1}{4}

k = \frac{- 41 - 39}{2 \cdot 4} : - 10

The solutions to the quadratic equation are:

k = - \frac{1}{4}, k = - 10

x^{2} - 6 x + 5 = - 4

3 k^{2} - 4 k - 4 = k

(3 x + 9)^{2} = 81

k (x) = 2 x^{2} + 3 x - 1, f (x, h) (a + h)

(3 x - 2)^{2} = (2 x + 2)^{2} + x^{2}

What are the solutions to the equation 4k^2+41k+10=0 ?
The solutions to the equation 4k^2+41k+10=0 are k=-1/4 ,k=-10
Find the zeros of 4k^2+41k+10=0
The zeros of 4k^2+41k+10=0 are k=-1/4 ,k=-10