What are the solutions to the equation x^2-6x+5=-4 ?

The solutions to the equation x^2-6x+5=-4 are x=3

Find the zeros of x^2-6x+5=-4

The zeros of x^2-6x+5=-4 are x=3

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x^{2} - 6 x + 5 = - 4

x = 3

Solution steps

x^{2} - 6 x + 5 = - 4

Move

4

to the left side

x^{2} - 6 x + 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 1 \cdot 9}{2 \cdot 1}

(- 6)^{2} - 4 \cdot 1 \cdot 9 = 0

x_{1, 2} = \frac{- ( - 6 ) \pm 0}{2 \cdot 1}

x = \frac{- ( - 6 )}{2 \cdot 1}

\frac{- ( - 6 )}{2 \cdot 1} = 3

x = 3

The solution to the quadratic equation is:

x = 3

3 k^{2} - 4 k - 4 = k

(3 x + 9)^{2} = 81

k (x) = 2 x^{2} + 3 x - 1, f (x, h) (a + h)

(3 x - 2)^{2} = (2 x + 2)^{2} + x^{2}

2 m^{2} - 8 m = 0

What are the solutions to the equation x^2-6x+5=-4 ?
The solutions to the equation x^2-6x+5=-4 are x=3
Find the zeros of x^2-6x+5=-4
The zeros of x^2-6x+5=-4 are x=3