What are the solutions to the equation (3x+9)^2=81 ?

The solutions to the equation (3x+9)^2=81 are x=0,x=-6

Find the zeros of (3x+9)^2=81

The zeros of (3x+9)^2=81 are x=0,x=-6

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(3 x + 9)^{2} = 81

x = 0, x = - 6

Solution steps

(3 x + 9)^{2} = 81

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

3 x + 9 = 81 : x = 0

Solve

3 x + 9 = - 81 : x = - 6

The solutions to the quadratic equation are:

x = 0, x = - 6

k (x) = 2 x^{2} + 3 x - 1, f (x, h) (a + h)

(3 x - 2)^{2} = (2 x + 2)^{2} + x^{2}

2 m^{2} - 8 m = 0

4 - 2 x + 3 x^{2} = 0

x, y = \frac{x ^{2}}{4}

What are the solutions to the equation (3x+9)^2=81 ?
The solutions to the equation (3x+9)^2=81 are x=0,x=-6
Find the zeros of (3x+9)^2=81
The zeros of (3x+9)^2=81 are x=0,x=-6