What are the solutions to the equation 4x^2=60x ?

The solutions to the equation 4x^2=60x are x=0,x=15

Find the zeros of 4x^2=60x

The zeros of 4x^2=60x are x=0,x=15

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4 x^{2} = 60 x

x = 0, x = 15

Solution steps

4 x^{2} = 60 x

Move

60 x

to the left side

4 x^{2} - 60 x = 0

Factor

4 x^{2} - 60 x : 4 x (x - 15)

4 x (x - 15) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x - 15 = 0

Solve

x - 15 = 0 : x = 15

The solutions to the quadratic equation are:

x = 0, x = 15

3 x^{2} + 5 (2 x + 1) = 0

- 2 (x - 6)^{2} + 7 = - 23

(\frac{2}{3}) x^{2} + 5 x - 9 = 0

r^{2} + 10 r - 18 = 61

h^{2} - 4 h - 32 = 0

What are the solutions to the equation 4x^2=60x ?
The solutions to the equation 4x^2=60x are x=0,x=15
Find the zeros of 4x^2=60x
The zeros of 4x^2=60x are x=0,x=15