What are the solutions to the equation 4^2+b^2=10^2 ?

The solutions to the equation 4^2+b^2=10^2 are b=2sqrt(21),b=-2sqrt(21)

Find the zeros of 4^2+b^2=10^2

The zeros of 4^2+b^2=10^2 are b=2sqrt(21),b=-2sqrt(21)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

4^{2} + b^{2} = 1 0^{2}

b = 221, b = - 221

Decimal Notation

b = 9.16515 \dots, b = - 9.16515 \dots

Solution steps

4^{2} + b^{2} = 1 0^{2}

Move

4^{2}

to the right side

b^{2} = 84

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

b = 84, b = - 84

84 = 221

- 84 = - 221

b = 221, b = - 221

3 x - 5 x^{2} + 1 = x - 7

5 a^{2} - 3 a + 6 = 2

0 = 7 x^{2} - 2 x - 1

a, a^{2} + 2 ab - b^{2} = 0

t^{2} - 4.5 t + 3.5 = 0

What are the solutions to the equation 4^2+b^2=10^2 ?
The solutions to the equation 4^2+b^2=10^2 are b=2sqrt(21),b=-2sqrt(21)
Find the zeros of 4^2+b^2=10^2
The zeros of 4^2+b^2=10^2 are b=2sqrt(21),b=-2sqrt(21)