What are the solutions to the equation completesquare 2x^2-3x-4=0 ?

The solutions to the equation completesquare 2x^2-3x-4=0 are x=(sqrt(41)+3)/4 ,x=(-sqrt(41)+3)/4

Find the zeros of completesquare 2x^2-3x-4=0

The zeros of completesquare 2x^2-3x-4=0 are x=(sqrt(41)+3)/4 ,x=(-sqrt(41)+3)/4

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2 x^{2} - 3 x - 4 = 0

x = \frac{41 + 3}{4}, x = \frac{- 41 + 3}{4}

Decimal Notation

x = 2.35078 \dots, x = - 0.85078 \dots

Solution steps

2 x^{2} - 3 x - 4 = 0

Move

4

to the right side

2 x^{2} - 3 x = 4

Divide both sides by

2

\frac{2 x ^{2} - 3 x}{2} = \frac{4}{2}

x^{2} - \frac{3 x}{2} = 2

Rewrite in the form

(x + a)^{2} = b

(x - \frac{3}{4})^{2} = \frac{41}{16}

For

the solutions are

f (x) = a, - a

Solve

x - \frac{3}{4} = \frac{41}{16} : x = \frac{41 + 3}{4}

Solve

x - \frac{3}{4} = - \frac{41}{16} : x = \frac{- 41 + 3}{4}

The solutions to the quadratic equation are:

x = \frac{41 + 3}{4}, x = \frac{- 41 + 3}{4}

x, 7 x^{2} - x = 7

g^{2} - 11 g - 42 = 0

(x - 2) (2 x + 5) = 0

15 x^{2} + 17 x - 4 = 0

2 x^{2} - 12 x + 1

What are the solutions to the equation completesquare 2x^2-3x-4=0 ?
The solutions to the equation completesquare 2x^2-3x-4=0 are x=(sqrt(41)+3)/4 ,x=(-sqrt(41)+3)/4
Find the zeros of completesquare 2x^2-3x-4=0
The zeros of completesquare 2x^2-3x-4=0 are x=(sqrt(41)+3)/4 ,x=(-sqrt(41)+3)/4