What are the solutions to the equation x^2-3x+2=x-1 ?

The solutions to the equation x^2-3x+2=x-1 are x=3,x=1

Find the zeros of x^2-3x+2=x-1

The zeros of x^2-3x+2=x-1 are x=3,x=1

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x^{2} - 3 x + 2 = x - 1

x = 3, x = 1

Solution steps

x^{2} - 3 x + 2 = x - 1

Move

1

to the left side

x^{2} - 3 x + 3 = x

Move

x

to the left side

x^{2} - 4 x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot 3}{2 \cdot 1}

(- 4)^{2} - 4 \cdot 1 \cdot 3 = 2

x_{1, 2} = \frac{- ( - 4 ) \pm 2}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 2}{2 \cdot 1}, x_{2} = \frac{- ( - 4 ) - 2}{2 \cdot 1}

x = \frac{- ( - 4 ) + 2}{2 \cdot 1} : 3

x = \frac{- ( - 4 ) - 2}{2 \cdot 1} : 1

The solutions to the quadratic equation are:

x = 3, x = 1

2 x^{2} - 3 x - 4 = 0

x, 7 x^{2} - x = 7

g^{2} - 11 g - 42 = 0

(x - 2) (2 x + 5) = 0

15 x^{2} + 17 x - 4 = 0

What are the solutions to the equation x^2-3x+2=x-1 ?
The solutions to the equation x^2-3x+2=x-1 are x=3,x=1
Find the zeros of x^2-3x+2=x-1
The zeros of x^2-3x+2=x-1 are x=3,x=1