What are the solutions to the equation x(2x+4)+5x=-7 ?

The solutions to the equation x(2x+4)+5x=-7 are x=-1,x=-7/2

Find the zeros of x(2x+4)+5x=-7

The zeros of x(2x+4)+5x=-7 are x=-1,x=-7/2

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x (2 x + 4) + 5 x = - 7

x = - 1, x = - \frac{7}{2}

Decimal Notation

x = - 1, x = - 3.5

Solution steps

x (2 x + 4) + 5 x = - 7

Expand

x (2 x + 4) + 5 x : 2 x^{2} + 9 x

2 x^{2} + 9 x = - 7

Move

7

to the left side

2 x^{2} + 9 x + 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 \cdot 2 \cdot 7}{2 \cdot 2}

9^{2} - 4 \cdot 2 \cdot 7 = 5

x_{1, 2} = \frac{- 9 \pm 5}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 9 + 5}{2 \cdot 2}, x_{2} = \frac{- 9 - 5}{2 \cdot 2}

x = \frac{- 9 + 5}{2 \cdot 2} : - 1

x = \frac{- 9 - 5}{2 \cdot 2} : - \frac{7}{2}

The solutions to the quadratic equation are:

x = - 1, x = - \frac{7}{2}

9 x^{2} + 18 x + 82 = 0

2.5 (x + 1)^{2} = 6 x^{2}

x^{2} - 18 - 3 x = 0

R^{2} + 7 R + 12 = 0

4 y^{2} - 9 y + 2 = 0

What are the solutions to the equation x(2x+4)+5x=-7 ?
The solutions to the equation x(2x+4)+5x=-7 are x=-1,x=-7/2
Find the zeros of x(2x+4)+5x=-7
The zeros of x(2x+4)+5x=-7 are x=-1,x=-7/2