What are the solutions to the equation 225-(15-2x)^2=5447 ?

The solutions to the equation 225-(15-2x)^2=5447 are x= 15/2-isqrt(2611/2),x= 15/2+isqrt(2611/2)

Find the zeros of 225-(15-2x)^2=5447

The zeros of 225-(15-2x)^2=5447 are x= 15/2-isqrt(2611/2),x= 15/2+isqrt(2611/2)

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225 - (15 - 2 x)^{2} = 5447

x = \frac{15}{2} - i \frac{2611}{2}, x = \frac{15}{2} + i \frac{2611}{2}

Solution steps

225 - (15 - 2 x)^{2} = 5447

Move

225

to the right side

- (15 - 2 x)^{2} = 5222

Divide both sides by

- 1

(15 - 2 x)^{2} = - 5222

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

15 - 2 x = - 5222 : x = \frac{15}{2} - i \frac{2611}{2}

Solve

15 - 2 x = - - 5222 : x = \frac{15}{2} + i \frac{2611}{2}

The solutions to the quadratic equation are:

x = \frac{15}{2} - i \frac{2611}{2}, x = \frac{15}{2} + i \frac{2611}{2}

5 x^{2} + 5 x = 2 x^{2} + 10 x

3 (x + 4)^{2} = 54

x, f (x + 3) = 3 x^{2} + 4 x - 3

9 x^{2} + 48 x + 65 = 0

3 b^{2} - 15 = 4 b

What are the solutions to the equation 225-(15-2x)^2=5447 ?
The solutions to the equation 225-(15-2x)^2=5447 are x= 15/2-isqrt(2611/2),x= 15/2+isqrt(2611/2)
Find the zeros of 225-(15-2x)^2=5447
The zeros of 225-(15-2x)^2=5447 are x= 15/2-isqrt(2611/2),x= 15/2+isqrt(2611/2)