What are the solutions to the equation 3b^2-15=4b ?

The solutions to the equation 3b^2-15=4b are b=3,b=-5/3

Find the zeros of 3b^2-15=4b

The zeros of 3b^2-15=4b are b=3,b=-5/3

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3 b^{2} - 15 = 4 b

b = 3, b = - \frac{5}{3}

Decimal Notation

b = 3, b = - 1.66666 \dots

Solution steps

3 b^{2} - 15 = 4 b

Move

4 b

to the left side

3 b^{2} - 15 - 4 b = 0

Write in the standard form

a x^{2} + b x + c = 0

3 b^{2} - 4 b - 15 = 0

Solve with the quadratic formula

b_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 3 ( - 15 )}{2 \cdot 3}

(- 4)^{2} - 4 \cdot 3 (- 15) = 14

b_{1, 2} = \frac{- ( - 4 ) \pm 14}{2 \cdot 3}

Separate the solutions

b_{1} = \frac{- ( - 4 ) + 14}{2 \cdot 3}, b_{2} = \frac{- ( - 4 ) - 14}{2 \cdot 3}

b = \frac{- ( - 4 ) + 14}{2 \cdot 3} : 3

b = \frac{- ( - 4 ) - 14}{2 \cdot 3} : - \frac{5}{3}

The solutions to the quadratic equation are:

b = 3, b = - \frac{5}{3}

t, S = \frac{1}{2} g t^{2}

5 p^{2} + 36 = 441

(x - 2) (x - 10) = - 16

m^{2} - 6 m + 5 = 4 m^{2} - 8

w^{2} + 8 w + 7 = 0

What are the solutions to the equation 3b^2-15=4b ?
The solutions to the equation 3b^2-15=4b are b=3,b=-5/3
Find the zeros of 3b^2-15=4b
The zeros of 3b^2-15=4b are b=3,b=-5/3