What are the solutions to the equation 9x^2+48x+65=0 ?

The solutions to the equation 9x^2+48x+65=0 are x=-8/3+i 1/3 ,x=-8/3-i 1/3

Find the zeros of 9x^2+48x+65=0

The zeros of 9x^2+48x+65=0 are x=-8/3+i 1/3 ,x=-8/3-i 1/3

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9 x^{2} + 48 x + 65 = 0

x = - \frac{8}{3} + i \frac{1}{3}, x = - \frac{8}{3} - i \frac{1}{3}

Solution steps

9 x^{2} + 48 x + 65 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 48 \pm 4 8 ^{2} - 4 \cdot 9 \cdot 65}{2 \cdot 9}

Simplify

4 8^{2} - 4 \cdot 9 \cdot 65 : 6 i

x_{1, 2} = \frac{- 48 \pm 6 i}{2 \cdot 9}

Separate the solutions

x_{1} = \frac{- 48 + 6 i}{2 \cdot 9}, x_{2} = \frac{- 48 - 6 i}{2 \cdot 9}

x = \frac{- 48 + 6 i}{2 \cdot 9} : - \frac{8}{3} + i \frac{1}{3}

x = \frac{- 48 - 6 i}{2 \cdot 9} : - \frac{8}{3} - i \frac{1}{3}

The solutions to the quadratic equation are:

x = - \frac{8}{3} + i \frac{1}{3}, x = - \frac{8}{3} - i \frac{1}{3}

3 b^{2} - 15 = 4 b

t, S = \frac{1}{2} g t^{2}

5 p^{2} + 36 = 441

(x - 2) (x - 10) = - 16

m^{2} - 6 m + 5 = 4 m^{2} - 8

What are the solutions to the equation 9x^2+48x+65=0 ?
The solutions to the equation 9x^2+48x+65=0 are x=-8/3+i 1/3 ,x=-8/3-i 1/3
Find the zeros of 9x^2+48x+65=0
The zeros of 9x^2+48x+65=0 are x=-8/3+i 1/3 ,x=-8/3-i 1/3