What are the solutions to the equation 3(x+4)^2=54 ?

The solutions to the equation 3(x+4)^2=54 are x=3sqrt(2)-4,x=-3sqrt(2)-4

Find the zeros of 3(x+4)^2=54

The zeros of 3(x+4)^2=54 are x=3sqrt(2)-4,x=-3sqrt(2)-4

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3 (x + 4)^{2} = 54

x = 32 - 4, x = - 32 - 4

Decimal Notation

x = 0.24264 \dots, x = - 8.24264 \dots

Solution steps

3 (x + 4)^{2} = 54

Divide both sides by

3

(x + 4)^{2} = 18

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 4 = 18 : x = 32 - 4

Solve

x + 4 = - 18 : x = - 32 - 4

The solutions to the quadratic equation are:

x = 32 - 4, x = - 32 - 4

x, f (x + 3) = 3 x^{2} + 4 x - 3

9 x^{2} + 48 x + 65 = 0

3 b^{2} - 15 = 4 b

t, S = \frac{1}{2} g t^{2}

5 p^{2} + 36 = 441

What are the solutions to the equation 3(x+4)^2=54 ?
The solutions to the equation 3(x+4)^2=54 are x=3sqrt(2)-4,x=-3sqrt(2)-4
Find the zeros of 3(x+4)^2=54
The zeros of 3(x+4)^2=54 are x=3sqrt(2)-4,x=-3sqrt(2)-4