What are the solutions to the equation (x+1)(x-2)=3 ?

The solutions to the equation (x+1)(x-2)=3 are x=(1+sqrt(21))/2 ,x=(1-sqrt(21))/2

Find the zeros of (x+1)(x-2)=3

The zeros of (x+1)(x-2)=3 are x=(1+sqrt(21))/2 ,x=(1-sqrt(21))/2

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(x + 1) (x - 2) = 3

x = \frac{1 + 21}{2}, x = \frac{1 - 21}{2}

Decimal Notation

x = 2.79128 \dots, x = - 1.79128 \dots

Solution steps

(x + 1) (x - 2) = 3

Expand

(x + 1) (x - 2) : x^{2} - x - 2

x^{2} - x - 2 = 3

Move

3

to the left side

x^{2} - x - 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 1 \cdot ( - 5 )}{2 \cdot 1}

(- 1)^{2} - 4 \cdot 1 \cdot (- 5) = 21

x_{1, 2} = \frac{- ( - 1 ) \pm 21}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 21}{2 \cdot 1}, x_{2} = \frac{- ( - 1 ) - 21}{2 \cdot 1}

x = \frac{- ( - 1 ) + 21}{2 \cdot 1} : \frac{1 + 21}{2}

x = \frac{- ( - 1 ) - 21}{2 \cdot 1} : \frac{1 - 21}{2}

The solutions to the quadratic equation are:

x = \frac{1 + 21}{2}, x = \frac{1 - 21}{2}

\frac{a + c x ^{2}}{b} = x^{2}

12 x^{2} - 55 x + 28 = 0

(2 x - 6)^{2} = 0

0 = 6 x^{2} + x - 1

2 x^{2} - 3 x - 32 = 0

What are the solutions to the equation (x+1)(x-2)=3 ?
The solutions to the equation (x+1)(x-2)=3 are x=(1+sqrt(21))/2 ,x=(1-sqrt(21))/2
Find the zeros of (x+1)(x-2)=3
The zeros of (x+1)(x-2)=3 are x=(1+sqrt(21))/2 ,x=(1-sqrt(21))/2