What are the solutions to the equation x(2+2x)=60 ?

The solutions to the equation x(2+2x)=60 are x=5,x=-6

Find the zeros of x(2+2x)=60

The zeros of x(2+2x)=60 are x=5,x=-6

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x (2 + 2 x) = 60

x = 5, x = - 6

Solution steps

x (2 + 2 x) = 60

Expand

x (2 + 2 x) : 2 x + 2 x^{2}

2 x + 2 x^{2} = 60

Move

60

to the left side

2 x + 2 x^{2} - 60 = 0

Write in the standard form

a x^{2} + b x + c = 0

2 x^{2} + 2 x - 60 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 2 ( - 60 )}{2 \cdot 2}

2^{2} - 4 \cdot 2 (- 60) = 22

x_{1, 2} = \frac{- 2 \pm 22}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 2 + 22}{2 \cdot 2}, x_{2} = \frac{- 2 - 22}{2 \cdot 2}

x = \frac{- 2 + 22}{2 \cdot 2} : 5

x = \frac{- 2 - 22}{2 \cdot 2} : - 6

The solutions to the quadratic equation are:

x = 5, x = - 6

y^{2} - 4 y + 29 = 0

4 x^{2} - 27 x = 0

5 (y - 5)^{2} = 245

3 x^{2} - 13 x + 5 = 0

x^{2} + (m + n) x + mn = 0

What are the solutions to the equation x(2+2x)=60 ?
The solutions to the equation x(2+2x)=60 are x=5,x=-6
Find the zeros of x(2+2x)=60
The zeros of x(2+2x)=60 are x=5,x=-6