What are the solutions to the equation x^2+(m+n)x+mn=0 ?

The solutions to the equation x^2+(m+n)x+mn=0 are x=-n,x=-m

Find the zeros of x^2+(m+n)x+mn=0

The zeros of x^2+(m+n)x+mn=0 are x=-n,x=-m

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x^{2} + (m + n) x + mn = 0

x = - n, x = - m

Solution steps

x^{2} + (m + n) x + mn = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( m + n ) \pm ( m + n ) ^{2} - 4 \cdot 1 \cdot mn}{2 \cdot 1}

Simplify

(m + n)^{2} - 4 \cdot 1 \cdot mn : m - n

x_{1, 2} = \frac{- ( m + n ) \pm ( m - n )}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( m + n ) + m - n}{2 \cdot 1}, x_{2} = \frac{- ( m + n ) - ( m - n )}{2 \cdot 1}

x = \frac{- ( m + n ) + m - n}{2 \cdot 1} : - n

x = \frac{- ( m + n ) - ( m - n )}{2 \cdot 1} : - m

The solutions to the quadratic equation are:

x = - n, x = - m

6 x^{2} + 5 x - 12 = 0

(3 x + 6) (x + 8) = 6 x (x + 5)

2 s^{2} = 7 s + 4

3 m^{2} - 9 m + 16 = 0

x^{2} - (x - 1) = 31

What are the solutions to the equation x^2+(m+n)x+mn=0 ?
The solutions to the equation x^2+(m+n)x+mn=0 are x=-n,x=-m
Find the zeros of x^2+(m+n)x+mn=0
The zeros of x^2+(m+n)x+mn=0 are x=-n,x=-m