What are the solutions to the equation 3x^2-13x+5=0 ?

The solutions to the equation 3x^2-13x+5=0 are x=(13+sqrt(109))/6 ,x=(13-sqrt(109))/6

Find the zeros of 3x^2-13x+5=0

The zeros of 3x^2-13x+5=0 are x=(13+sqrt(109))/6 ,x=(13-sqrt(109))/6

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3 x^{2} - 13 x + 5 = 0

x = \frac{13 + 109}{6}, x = \frac{13 - 109}{6}

Decimal Notation

x = 3.90671 \dots, x = 0.42661 \dots

Solution steps

3 x^{2} - 13 x + 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 13 ) \pm ( - 13 ) ^{2} - 4 \cdot 3 \cdot 5}{2 \cdot 3}

(- 13)^{2} - 4 \cdot 3 \cdot 5 = 109

x_{1, 2} = \frac{- ( - 13 ) \pm 109}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 13 ) + 109}{2 \cdot 3}, x_{2} = \frac{- ( - 13 ) - 109}{2 \cdot 3}

x = \frac{- ( - 13 ) + 109}{2 \cdot 3} : \frac{13 + 109}{6}

x = \frac{- ( - 13 ) - 109}{2 \cdot 3} : \frac{13 - 109}{6}

The solutions to the quadratic equation are:

x = \frac{13 + 109}{6}, x = \frac{13 - 109}{6}

x^{2} + (m + n) x + mn = 0

6 x^{2} + 5 x - 12 = 0

(3 x + 6) (x + 8) = 6 x (x + 5)

2 s^{2} = 7 s + 4

3 m^{2} - 9 m + 16 = 0

What are the solutions to the equation 3x^2-13x+5=0 ?
The solutions to the equation 3x^2-13x+5=0 are x=(13+sqrt(109))/6 ,x=(13-sqrt(109))/6
Find the zeros of 3x^2-13x+5=0
The zeros of 3x^2-13x+5=0 are x=(13+sqrt(109))/6 ,x=(13-sqrt(109))/6