What are the solutions to the equation 5(y-5)^2=245 ?

The solutions to the equation 5(y-5)^2=245 are y=12,y=-2

Find the zeros of 5(y-5)^2=245

The zeros of 5(y-5)^2=245 are y=12,y=-2

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5 (y - 5)^{2} = 245

y = 12, y = - 2

Solution steps

5 (y - 5)^{2} = 245

Divide both sides by

5

(y - 5)^{2} = 49

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

y - 5 = 49 : y = 12

Solve

y - 5 = - 49 : y = - 2

The solutions to the quadratic equation are:

y = 12, y = - 2

3 x^{2} - 13 x + 5 = 0

x^{2} + (m + n) x + mn = 0

6 x^{2} + 5 x - 12 = 0

(3 x + 6) (x + 8) = 6 x (x + 5)

2 s^{2} = 7 s + 4

What are the solutions to the equation 5(y-5)^2=245 ?
The solutions to the equation 5(y-5)^2=245 are y=12,y=-2
Find the zeros of 5(y-5)^2=245
The zeros of 5(y-5)^2=245 are y=12,y=-2