What are the solutions to the equation 6x^2+5x-12=0 ?

The solutions to the equation 6x^2+5x-12=0 are x=(-5+sqrt(313))/(12),x=(-5-sqrt(313))/(12)

Find the zeros of 6x^2+5x-12=0

The zeros of 6x^2+5x-12=0 are x=(-5+sqrt(313))/(12),x=(-5-sqrt(313))/(12)

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6 x^{2} + 5 x - 12 = 0

x = \frac{- 5 + 313}{12}, x = \frac{- 5 - 313}{12}

Decimal Notation

x = 1.05765 \dots, x = - 1.89098 \dots

Solution steps

6 x^{2} + 5 x - 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 6 ( - 12 )}{2 \cdot 6}

5^{2} - 4 \cdot 6 (- 12) = 313

x_{1, 2} = \frac{- 5 \pm 313}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- 5 + 313}{2 \cdot 6}, x_{2} = \frac{- 5 - 313}{2 \cdot 6}

x = \frac{- 5 + 313}{2 \cdot 6} : \frac{- 5 + 313}{12}

x = \frac{- 5 - 313}{2 \cdot 6} : \frac{- 5 - 313}{12}

The solutions to the quadratic equation are:

x = \frac{- 5 + 313}{12}, x = \frac{- 5 - 313}{12}

(3 x + 6) (x + 8) = 6 x (x + 5)

2 s^{2} = 7 s + 4

3 m^{2} - 9 m + 16 = 0

x^{2} - (x - 1) = 31

2.1 x^{2} + 9 x = 4

What are the solutions to the equation 6x^2+5x-12=0 ?
The solutions to the equation 6x^2+5x-12=0 are x=(-5+sqrt(313))/(12),x=(-5-sqrt(313))/(12)
Find the zeros of 6x^2+5x-12=0
The zeros of 6x^2+5x-12=0 are x=(-5+sqrt(313))/(12),x=(-5-sqrt(313))/(12)