What are the solutions to the equation 3m^2-9m+16=0 ?

The solutions to the equation 3m^2-9m+16=0 are m= 3/2+i(sqrt(111))/6 ,m= 3/2-i(sqrt(111))/6

Find the zeros of 3m^2-9m+16=0

The zeros of 3m^2-9m+16=0 are m= 3/2+i(sqrt(111))/6 ,m= 3/2-i(sqrt(111))/6

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3 m^{2} - 9 m + 16 = 0

m = \frac{3}{2} + i \frac{111}{6}, m = \frac{3}{2} - i \frac{111}{6}

Solution steps

3 m^{2} - 9 m + 16 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 \cdot 3 \cdot 16}{2 \cdot 3}

Simplify

(- 9)^{2} - 4 \cdot 3 \cdot 16 : 111 i

m_{1, 2} = \frac{- ( - 9 ) \pm 111 i}{2 \cdot 3}

Separate the solutions

m_{1} = \frac{- ( - 9 ) + 111 i}{2 \cdot 3}, m_{2} = \frac{- ( - 9 ) - 111 i}{2 \cdot 3}

m = \frac{- ( - 9 ) + 111 i}{2 \cdot 3} : \frac{3}{2} + i \frac{111}{6}

m = \frac{- ( - 9 ) - 111 i}{2 \cdot 3} : \frac{3}{2} - i \frac{111}{6}

The solutions to the quadratic equation are:

m = \frac{3}{2} + i \frac{111}{6}, m = \frac{3}{2} - i \frac{111}{6}

x^{2} - (x - 1) = 31

2.1 x^{2} + 9 x = 4

a, a^{2} - ab - 12 b^{2} = 0

2 y^{2} + y = 0

10 x^{2} = 45 - 68 x

What are the solutions to the equation 3m^2-9m+16=0 ?
The solutions to the equation 3m^2-9m+16=0 are m= 3/2+i(sqrt(111))/6 ,m= 3/2-i(sqrt(111))/6
Find the zeros of 3m^2-9m+16=0
The zeros of 3m^2-9m+16=0 are m= 3/2+i(sqrt(111))/6 ,m= 3/2-i(sqrt(111))/6