What are the solutions to the equation x^2-(x-1)=31 ?

The solutions to the equation x^2-(x-1)=31 are x=6,x=-5

Find the zeros of x^2-(x-1)=31

The zeros of x^2-(x-1)=31 are x=6,x=-5

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x^{2} - (x - 1) = 31

x = 6, x = - 5

Solution steps

x^{2} - (x - 1) = 31

Expand

x^{2} - (x - 1) : x^{2} - x + 1

x^{2} - x + 1 = 31

Move

31

to the left side

x^{2} - x - 30 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 1 \cdot ( - 30 )}{2 \cdot 1}

(- 1)^{2} - 4 \cdot 1 \cdot (- 30) = 11

x_{1, 2} = \frac{- ( - 1 ) \pm 11}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 11}{2 \cdot 1}, x_{2} = \frac{- ( - 1 ) - 11}{2 \cdot 1}

x = \frac{- ( - 1 ) + 11}{2 \cdot 1} : 6

x = \frac{- ( - 1 ) - 11}{2 \cdot 1} : - 5

The solutions to the quadratic equation are:

x = 6, x = - 5

2.1 x^{2} + 9 x = 4

a, a^{2} - ab - 12 b^{2} = 0

2 y^{2} + y = 0

10 x^{2} = 45 - 68 x

[f (a)]^{2} = 5 x^{2} - x + 3

What are the solutions to the equation x^2-(x-1)=31 ?
The solutions to the equation x^2-(x-1)=31 are x=6,x=-5
Find the zeros of x^2-(x-1)=31
The zeros of x^2-(x-1)=31 are x=6,x=-5