What are the solutions to the equation -x^2-6x=5 ?

The solutions to the equation -x^2-6x=5 are x=-5,x=-1

Find the zeros of -x^2-6x=5

The zeros of -x^2-6x=5 are x=-5,x=-1

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- x^{2} - 6 x = 5

x = - 5, x = - 1

Solution steps

- x^{2} - 6 x = 5

Move

5

to the left side

- x^{2} - 6 x - 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 ( - 1 ) ( - 5 )}{2 ( - 1 )}

(- 6)^{2} - 4 (- 1) (- 5) = 4

x_{1, 2} = \frac{- ( - 6 ) \pm 4}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 4}{2 ( - 1 )}, x_{2} = \frac{- ( - 6 ) - 4}{2 ( - 1 )}

x = \frac{- ( - 6 ) + 4}{2 ( - 1 )} : - 5

x = \frac{- ( - 6 ) - 4}{2 ( - 1 )} : - 1

The solutions to the quadratic equation are:

x = - 5, x = - 1

3 x^{2} - 9 x = - 4

(5 x + 2)^{2} - 12 = 0

a^{2} - 12 a + 20 = 0

x^{2} + 2 x = - x + 4

(x - 4)^{2} - 13 = 0

What are the solutions to the equation -x^2-6x=5 ?
The solutions to the equation -x^2-6x=5 are x=-5,x=-1
Find the zeros of -x^2-6x=5
The zeros of -x^2-6x=5 are x=-5,x=-1